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Mentoring Program Curriculum (1)
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Maths AA
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Topics
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1. Number and Algebra
/
Sub-topics
Mentoring Program Curriculum (1)
/
Subjects
/
Maths AA
/
Topics
/
1. Number and Algebra
/
Sub-topics
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•
Arithmetic sequences and series (1.2)
•
Use of the formulae for the
n
t
h
n^{th}
n
t
h
term and the sum of the first
n
n
n
terms of the sequence.
•
Use of sigma notations of sums of arithmetic sequences.
•
Applications
•
Analysis, interpretation and prediction where a model is not perfectly arithmetic in real life.
•
Geometric sequences and series. (1.3)
•
Use of the formulae for the
n
t
h
n^{th}
n
t
h
term and the sum of the first
n
n
n
terms of the sequence.
•
Use of sigma notation for the sums of geometric sequences.
•
Applications
•
Financial applications of geometric sequences and series: ie) compound interest, annual depreciation. (1.4)
Δ
θ
=
Arc
Radius
Δ
θ
=
Δ
s
r
and
Δ
θ
⋅
r
=
Δ
s
\begin{aligned} &\Delta \theta=\frac{\text { Arc }}{\text { Radius }}\\ &\Delta \boldsymbol{\theta}=\frac{\Delta \boldsymbol{s}}{r} \text { and } \boldsymbol{\Delta} \boldsymbol{\theta} \cdot \boldsymbol{r}=\boldsymbol{\Delta} \boldsymbol{s} \end{aligned}
Δ
θ
=
Radius
Arc
Δ
θ
=
r
Δ
s
and
Δ
θ
⋅
r
=
Δ
s
Sequence
a
n
a_n
a
n
is an enumerated collection of objects in which repetitions are allowed and order matters.
There are two sequences to be aware of:
arithmetic
and
geometric
.
1.2 Sequences and Series
•
Simple deductive proof, numerical and algebraic; how to lay out a left-hand side to right-hand side (LHS to RHS) proof. (1.6)
•
The symbols and notation for equality and identity.
•
Proof by mathematical induction (AHL 1.15)
•
Proof by contradiction
•
Use of a counterexample to show that a statement is not always true.
Notation
Definition
N
N
N
The set of natural numbers
Z
Z
Z
The set of integers
Q
Q
Q
The set of rational numbers (quotients)
R
R
R
The set of real numbers
Terminology
Definition
Proposition
A True of False statement
Not
¬
\neg
¬
Simply, a negation. For instance,
¬
p
\neg p
¬
p
will be false if
p
p
p
is true.
And
∧
\land
∧
Both propositions
p
p
p
and
q
q
q
must be true for “
p
p
p
and
q
q
q
” statement to be true.
Or
∨
\lor
∨
Either one of
p
p
p
or
q
q
q
can be true for “
p
p
p
or
q
q
q
” statement to be true.
Implication
p
⇒
q
p⇒ q
p
⇒
q
denotes “
If
p
p
p
,
then
q
q
q
”.
Antecedent
The sufficient condition in the implication, i.e.
p
p
p
in
p
⇒
q
p⇒ q
p
⇒
q
Consequent
The necessary condition in the implication, i.e.
p
⇒
q
p⇒ q
p
⇒
q
Logical Equivalence
p
⇔
q
p \Leftrightarrow q
p
⇔
q
. This is also written as “
if and only if
”, or “
iff
”.
Converse
A converse of logical statement; the converse of
p
⇒
q
p⇒q
p
⇒
q
is
q
⇒
p
q⇒p
q
⇒
p
The converse is not necessarily true even if
p
⇒
q
p⇒q
p
⇒
q
is true; i.e.
p
⇒
q
⇏
q
⇒
p
p⇒ q ⇏ q⇒ p
p
⇒
q
⇏
q
⇒
p
Contrapositive
A negated converse of logical statements. The contrapositive of
p
⇒
q
p⇒q
p
⇒
q
is
¬
q
⇒
¬
p
\neg{q}⇒\neg{p}
¬
q
⇒
¬
p
. This has the same truth value as the statement
p
⇒
q
p⇒q
p
⇒
q
.
Methods
Steps
Direct proof
Given
p
⇒
q
p⇒q
p
⇒
q
, start from
p
p
p
to arrive at
q
q
q
. When you are proving
p
⇒
q
p⇒q
p
⇒
q
,
never
assume
q
q
q
when beginning your proof. You
cannot
start from the consequent and derive the antecedent. If it seems easy to prove the converse
q
⇒
p
q⇒p
q
⇒
p
, use backward reasoning
if possible
. Note that you have to prove
both
implications
p
⇒
q
p⇒q
p
⇒
q
and
q
⇒
p
q⇒p
q
⇒
p
when proving
p
⇔
q
p\Leftrightarrow q
p
⇔
q
. Direct proof questions typically involve demonstrating that a statement holds true for all integers, consecutive integers, or specific subsets such as even or odd numbers. You can start from letting an integer equal to or either
2
n
2n
2
n
(even integer) or
2
n
+
1
2n+1
2
n
+
1
(odd integer) for conventions.
Proof by contradiction
1. Given
p
p
p
, assume
¬
p
\neg p
¬
p
is true. •
n
n
n
is rational ⇒ Assume
n
n
n
is irrational. • If
n
2
n^2
n
2
is odd then
n
n
n
is odd ⇒ Assume
n
2
n^2
n
2
is odd and
n
n
n
is even. 2. Find a contradiction in this logical statement. 3. Therefore, conclude that p is indeed true. Common questions include: • Irrational numbers • Prime numbers • Odds and evens • Maximum and minimum values
Proof of the contrapositive
Given
p
⇒
q
p⇒q
p
⇒
q
, prove
¬
q
⇒
¬
p
\neg{q}⇒\neg{p}
¬
q
⇒
¬
p
instead, and use the property of the contrapositive.
Proof by induction
Give the proposition
P
n
P_n
P
n
, defined for
n
≥
a
n ≥ a
n
≥
a
for
a
∈
Z
a∈Z
a
∈
Z
: 1. Prove the base case; i.e.
n
=
a
n=a
n
=
a
2. Suppose/ assume that
P
k
P_k
P
k
is true, and prove
P
k
⇒
P
k
+
1
P_k \Rightarrow P_{k+1}
P
k
⇒
P
k
+
1
•Suppose
n
=
k
n=k
n
=
k
is true for
k
≥
a
k≥ a
k
≥
a
for a ℤ •Let
n
=
k
+
1
n=k+1
n
=
k
+
1
3.As
P
a
P_a
P
a
is true and
P
k
+
1
P_{k+1}
P
k
+
1
is true whenever
P
k
P_k
P
k
is true,
P
n
P_n
P
n
must be true for all
n
≥
a
n ≥ a
n
≥
a
. Common questions include: •Sums of sequences
∑
r
=
1
n
f
(
r
)
=
g
(
n
)
\sum_{r=1}^nf(r)=g(n)
∑
r
=
1
n
f
(
r
)
=
g
(
n
)
, then use
∑
r
=
1
k
+
1
f
(
r
)
=
f
(
k
+
1
)
+
∑
r
=
1
k
f
(
r
)
\sum_{r=1}^{k+1} f(r) = f(k+1) + \sum_{r=1}^{k} f(r)
∑
r
=
1
k
+
1
f
(
r
)
=
f
(
k
+
1
)
+
∑
r
=
1
k
f
(
r
)
for induction •Divisibility of an expression
f
(
n
)
=
m
⋅
q
n
f(n)=m\cdot q_n
f
(
n
)
=
m
⋅
q
n
where
m
m
m
and
q
n
q_n
q
n
are integers, then use
a
k
+
1
=
a
⋅
a
k
a^{k+1}=a \cdot a^k
a
k
+
1
=
a
⋅
a
k
for induction •Complex numbers de Moivre’s theorem •Derivatives
f
(
n
)
(
x
)
=
g
(
x
)
f^{(n)}(x)=g(x)
f
(
n
)
(
x
)
=
g
(
x
)
, then use
f
(
k
+
1
)
(
x
)
=
d
d
x
(
f
(
k
)
(
x
)
)
f^{(k+1)}(x)=\frac {d}{dx}(f^{(k)}(x))
f
(
k
+
1
)
(
x
)
=
d
x
d
(
f
(
k
)
(
x
))
for induction
1.3 Proof and Reasoning
•
The binomial theorem: expansion of
(
a
+
b
)
n
(a + b)^n
(
a
+
b
)
n
,
n
∈
N
n ∈ N
n
∈
N
.
(1.9)
•
Use of Pascal’s triangle and
n
C
r
^nC_r
n
C
r
.
•
Counting principles, including permutations and combinations. (AHL 1.10)
•
Extension of the binomial theorem to fractional and negative indices, ie
(
a
+
b
)
n
(a + b)^n
(
a
+
b
)
n
,
n
∈
Q
n ∈ Q
n
∈
Q
.
Use of Pascal’s triangle
Figure 1.4.1
Pascal’s triangle
1.4 Binomial Theorems and Combinatorics
•
The number
i
i
i
, where
i
2
=
−
1
i^2=-1
i
2
=
−
1
.
(1.12)
•
Cartesian form
z
=
a
+
b
i
z = a + bi
z
=
a
+
bi
; the terms real part, imaginary part, conjugate, modulus and argument.
•
The complex plane.
•
Modulus–argument (polar) form:
z
=
r
(
cos
θ
+
i
sin
θ
)
=
r
c
i
s
θ
z = r(\cosθ + i\sinθ) = rcisθ
z
=
r
(
cos
θ
+
i
sin
θ
)
=
rc
i
s
θ
(1.13)
•
Euler form:
z
=
r
e
i
θ
z = re^{iθ}
z
=
r
e
i
θ
•
Sums, products and quotients in Cartesian, polar or Euler forms and their geometric interpretation.
•
Complex conjugate roots of quadratic and polynomial equations with real coefficients.
(1.14)
•
De Moivre’s theorem and its extension to rational exponents.
•
Powers and roots of complex numbers.
1.5 Complex Numbers (HL)
1.6 Linear Equations (HL)