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5.3 Application of Differential Calculus

Tags
Differentiation
Tangent
Optimization
Related rates
Kinematics
Euler's method
Maclaurin series
Trigonometric functions
Exponential and Logarithmic functions
Modelling
Graphs
Chain rule
Quotient rule
Product rule
There are different applications you need to be aware of.
Application
Steps
Tangents
Tangent at aa denotes the best approximating straight line to the curve at aa.
We must have two pieces of information to obtain the equation of a tangent:
1.
Point of contact (a,f(a))(a, f(a))
2.
The gradient of a tangent at that point: f(a) f'(a)
Then, use yy0=m(xx0)y - y_0 = m(x-x_0) to obtain the equation of the tangent.
Rate of change
dydx\frac {dy}{dx} represents the rate of change in yy respect to xx.
Optimization
1.
Represent the situation in a clear diagram. Label the variable.
2.
Construct a formula with the variable to be optimized as a subject. Write down what domain restrictions there are on xx.
3.
Calculate the minimum or maximum depending on the situation.
Related rates (HL)
1.
Represent the situation in a clear diagram. Label the variable. Identify which information you have, and what you need to calculate.
2.
Construct a formula with the variable and obtain the derivative.
3.
Substitute the values for the particular case.
*Note: angles must be in radian.
Kinematics is the study of motion; modeling and analyzing the motion of objects in a straight line.
Terms
Definition
Displacement ss m
A particle’s distance relative to a fixed point– usually the origin s(t)s(t) Displacement is zero when the object is at or has returned to the origin Displacement can be positive or negative Displacement can be found by integrating velocity: s(t)=v(t)dts(t)=v(t)dt Use given initial conditions to solve the constant cc
Distance  dd m
Distance is always positive Distance traveled from aa to bb can be found by: abv(t)dt\int_a^b|v(t)|dt
Velocity vv ms⎺¹
The rate of change of a particle’s displacement at time tt v(t)=dsdtv(t)=\frac{ds}{dt} Velocity can be positive or negative depending on the direction of motion When the particle is stationary/ at rest, its velocity equals to zero Velocity can be found by differentiating s(t)s(t) or integrating a(t)a(t) v(t)=a(t)dtv(t)=\int a(t)dt Use given initial conditions to solve the constant cc
Speed v|v| ms⎺¹
The magnitude or absolute value of velocity–thus neglecting the direction of a particle
Acceleration aa ms⎺²
The rate of change of a particle’s velocity at time tt a(t)=dvdt=d2sdt2a(t)=\frac{dv}{dt}=\frac {d^2s}{dt^2}

Euler’s Method (HL)

This is a numerical method to solve dydx=f(x,y)\frac{dy}{dx}=f(x, y) with particular solution (x0,y0)(x_0, y_0).
Given the initial value, choosing the step size hh, we obtain the iith point:
1.
xi=xi1+hx_i=x_{i-1}+h
2.
yi=yi1+hf(xi1,yi1)y_i=y_{i-1}+hf(x_{i-1}, y_{i-1})
Figure 5.3.1 Numerical approximation of the gradients by Euler’s method
This creates a polygonal approximation to the solution curve.
We apply this iterative step n times to reach x=bx =b.
If nn \rightarrow ∞, from the fundamental theorem of calculus, we have: y(b)=y(x0)+x0bdydxdxy(b) =y(x_0)+\int_{x_0}^{b}\frac {dy}{dx}dx.
Construct an appropriate table of each iteration to apply Euler’s method using the calculator.
The last application is a series expansion of function ff, expressing ff as an infinite sum of polynomials.

Maclaurin series (HL)

The Maclaurin series is a Taylor series expansion of a function about 0.
f(x)=n=0f(n)(0)xnn!=f(0)+f(0)x+f(2)(0)2!x2+f(3)(0)3!x3+...f(x)=\sum_{n=0}^∞\frac{f^{(n)}(0)x^n}{n!}=f(0)+f'(0)x+\frac{f^{(2)}(0)}{2!}x^2+\frac{ f^{(3)}(0)}{3!}x^3+ ...
There are different types of method to approach this:
Method
Steps
Definition
1. Differentiate ff multiple times to find the pattern. 2. Apply the result to the general form.
Composite function
1. Notice if you are given the form f(g(x))f(g(x)) 2. Substitute the Maclaurin series of gg into the Maclaurin series of ff, and simplify.
Integration
1. Notice that your function f(x)f(x) can be found as an integration of a function of lower order, for instance, g(x)g(x).  2. Find the series of g(x)g(x) and integrate to find ff. This is because the Maclaurin series is analytic, i.e. infinitely differentiable/integrable.