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C.1 Simple Harmonic Motion

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2024/07/05 08:37
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C.1.1 Simple harmonic oscillations and its conditions

Oscillation: periodic motions which center around an equilibrium position
Wave: transfer of energy without transfer of matter
Simple harmonic motion (SHM): motion in which the restoring force (acceleration) is directly proportional to the displacement of the body from its equilibrium point
Period and amplitude are constant
Period is independent of amplitude
Sinusoidal (can be represented into sine or cosine graph)
C.1.1-1 2D diagrams and graphs that represents SHM in pendulum
Condition for simple harmonic motion:
A restoring force is required for simple harmonic motion to occur
A restoring force is a force directed towards the equilibrium position such that if the object is moved away from its equilibrium position, it will always be ‘pushed’ back towards that point.
Magnitude of restoring force is proportional to displacement and acts towards the equilibrium
Fx,F=kx(k=springconstant)F ∝-x, F=-kx (k=spring constant)
SinceF=ma,Since\, F=ma,
kx=ma,a=kmx-kx=ma,a= -\frac kmx
ax∴ a ∝-x
*The negative sign indicates that the acceleration always points towards the equilibrium.
C.1.1-2 Graph representing the relationship between acceleration and displacement in SHM
Angular Velocity
Vector measure of the rotation rate, which refers to how fast an object rotates or revolves relative to another point
Used for the relationship between restoring force and equilibrium in SHM
C.1.1-3 Diagram of angular velocity with notations
ω=θtθ=2π,t=T(T=period)ω=2πTf=1T(f=frequency)ω=2πf\omega = \frac{\theta}{t}\\ \theta = 2\pi, \quad t = T \quad (T = \textit{period})\\ \omega = \frac{2\pi}{T}\\ f = \frac{1}{T} \quad (f = \textit{{frequency}})\\ \omega = 2\pi f
Proof of Simple Harmonic Motion with Sine / Cosine graph
Sine Graph
C.1.1-4 Sine graph
C.1.1-5 Cosine graph
(x0=maximum displacement,ω=angular velocity)x=x0sin(ωt)v=dxdt=x0ωcos(ωt)a=dvdt=x0ω2sin(ωt)Sincex=x0sin(ωt)a=ω2x(x_0 = \textit{maximum displacement}, \quad \omega = \textit{angular velocity})\\ x = x_0 \cdot \sin(\omega t)\\ v = \frac{dx}{dt} = x_0 \cdot \omega \cdot \cos(\omega t)\\ a = \frac{dv}{dt} = - x_0 \cdot \omega^2 \cdot \sin(\omega t)\\ \text{Since} \quad x = x_0 \cdot \sin(\omega t)\\ a = -\omega^2 \cdot x
(x0=maximum displacement,ω=angular velocity)x=x0cos(ωt)v=dxdt=x0ωsin(ωt)a=dvdt=x0ω2cos(ωt)Sincex=x0cos(ωt)a=ω2x(x_0 = \textit{maximum displacement}, \quad \omega = \textit{angular velocity})\\ x = x_0 \cdot \cos(\omega t)\\ v = \frac{dx}{dt} = - x_0 \cdot \omega \cdot \sin(\omega t)\\ a = \frac{dv}{dt} = - x_0 \cdot \omega^2 \cdot \cos(\omega t)\\ \text{Since} \quad x = x_0 \cdot \cos(\omega t)\\ a = -\omega^2 \cdot x
So, the acceleration is directly proportional to negative displacement and is always directed towards equilibrium

C.1.1-5 Cosine graph

Simple Pendulum
Point mass hanging on a string/rod with negligible mass
C.1.1-6 Pendulum free body diagram with notations
F=mamgsin(θ)=maSincesin(θ)=xL(x=displacement,l=radius of pendulum)mg(xL)=mag(xL)=aSincea=ω2xω2x=g(xL)ω2=gL4π2T2=gLT2=4π2gLT=2πLgT=period,L=lengthofstring/rod,g=gravitationalacceleration9.81ms2F = ma\\ mg \sin(\theta) = ma\\ \text{Since}\,\sin(\theta) = \frac{x}{L} \,(x = \textit{displacement}, \,l = \textit{radius of pendulum})\\ mg \left(\frac{x}{L}\right) = ma\\ g \left(\frac{x}{L}\right) = a\\ \text{Since}\,a = - \omega^2 \cdot x\\ - \omega^2 \cdot x = - g \left(\frac{x}{L}\right)\\ \omega^{2} = \frac{g}{L}\\ \frac{4\pi^2}{T^2} = \frac{g}{L}\\ T^2 = 4\pi^2 \cdot \frac{g}{L}\\ T = 2\pi \sqrt{\frac{L}{g}}\\ T=period, L=length of string/rod, g=gravitational acceleration≈9.81ms^{-2}
Spring-Mass System
C.1.1-7 Diagrams representing SHM in spring
Fspring=kx(k=spring constant)SinceFweight=Fspringma=kxSince a=ω2xm(ω2x)=kxmω2=km(4π2T2)=kT2=4π2(mk)T=2πmkT=period,m=mass,k=spring constantF_{\text{spring}} = -kx \quad (k = \textit{spring constant})\\ \text{Since} \quad F_{\text{weight}} = F_{\text{spring}}\\ ma = - kx\\ \text{Since} \, a = - \omega^2 \cdot x\\ m(-\omega^2 \cdot x) = - kx m \omega^2 = k\\ m \left(\frac{4\pi^2}{T^2} \right) = k\\ T^2 = 4\pi^2 \cdot \left(\frac{m}{k} \right)\\ T = 2\pi \sqrt{\frac{m}{k}}\\ T = \textit{period}, \quad m = \textit{mass}, \quad k = \textit{spring constant}
⇒ for both two examples, it can be observed that period is independent of the amplitude

C.1.2 Time period, frequency, amplitude, displacement and phase difference

Definitions of key terminologies
Terminology
Definition
displacement, x
instantaneous distance from equilibrium with direction (change in position); [m]
amplitude, A
maximum displacement from the mean position (fixed average point); [m]
frequency, f
number of oscillations done per unit time; [Hz = s-1] (cycles per second)
period, T
time taken for one complete oscillation; [s] T=1fT=\frac1f
phase difference,
difference in phase angle of two waves; [rad] or [°] (deg) • in phase ⇒ ϕ=0 \phi=0 • out of phase ⇒ ϕ=π \phi=\pi or 180° (half a cycle) • one complete cycle is 2π2\pi or 360°

C.1.3 Graphs of simple harmonic motion

Acceleration, velocity, and displacement during SHM
C.1.3-1 variation of graphs that represent acceleration, velocity and displacement in SHM
acceleration leads velocity by 90° (=π2=\frac \pi2 )
velocity lags acceleration by 90°
velocity leads displacement by 90°
displacement lags velocity by 90°
acceleration and displacement are 180° out of phase ( ϕ=πor\phi=\pi \,or 180°)
Energy changes during simple harmonic motion
Energy is interchanged between kinetic energy (KE) and potential energy (PE) (or elastic potential energy, EPE).
∴ maximum value of KE or PE only can be total energy EtotalE_{total}
Assuming no resistive forces are applied to dissipate energy, total energy always remains constant.
Such oscillation is said to be undamped.
C.1.3-2 Straight line graph that represents the SHM
Energy in SHM is proportional to:
mass, mm
amplitude2,A2amplitude^{2}, A^{2}
frequency2,f2frequency^{2}, f^{2}
C.1.3-3 Variation of graphs that represents the KE, PE and total Energy
Time
Energy
t=0t=0
x=xmax=x0(x0=A)x=x_{max}=x_0 (x_0=A)KE=0KE=0EPE=12kA2=12kx02EPE=\frac12kA2=\frac12kx_0^2 Etotal=KE+EPE=0+12kA2=12kA2E_{total}=KE+EPE=0+\frac12kA^2=\frac12kA^2
t=14Tt=\frac 14T
x=0x=0EPE=12kx2=12k02=0EPE=\frac12kx^{2}=\frac12k0^2=0 Etotal=KE+EPE=12mvmax2+0=12kA2 E_{total}=KE+EPE=\frac12mv_{max}^2+0=\frac12kA^2 vmax=kmA2v_{\text{max}} = \sqrt{\frac{k}{m} A^2}
atanypoint xat\, any\, point\, x
EPE=12kx2EPE=\frac12kx^2Etotal=KE+EPE=0+12kx2=12kA2 E_{total}=KE+EPE=0+\frac12kx^2=\frac12kA^2 KE=12kA212kx2=12mv2KE=\frac12kA^2-\frac12kx^2=\frac12mv^2

C.1.4 Equation of SHM

Simple Harmonic Motion
Simple Harmonic Motion : A type of oscillation in which the acceleration on a body is proportional to its displacement, but acts in the opposite direction
aαxa \alpha -x
The conditions for an object to oscillate in SHM are that it shows :
Periodic oscillations
Acceleration proportional to its displacement
Acceleration in the opposite direction to its displaceme
C.1.4-1 Diagram of pendulum example of SHM
The relationship between the acceleration and displacement in simple harmonic motion can be defined by equation :
a=ω2xa = -\omega^2 x
(a=acceleration,ω=angularvelocity,x=displacement)(a=acceleration,\omega =angular velocity, x=displacement)
The equation shows the relationship between acceleration and displacement during simple harmonic motion :
The acceleration reaches its maximum value when the displacement is at a maximum
The minus sign shows that when the object is displacement to the right, the direction of the acceleration is to the left
Mathematic approach of SHM
When the graph of acceleration against displacement graph constructed we can notice that the graph shows straight line
C.1.4-2 annotated graph of acceleration and displacement in SHM
This shows that the acceleration of an object in simple harmonic motion is opposite but directly proportional to the negative displacement
The displacenemt, velocity and acceleration of object during simple harmonic motion can be represent by sin, cos and negative sin graph due to the calculus
C.1.4-3 Chart of graphs in SHM
C.1.4-4

C.1.5 Energy Changes in SHM

Energy Changes in Simple Harmonic Motion
During SHM, energy transition happens constantly between kinetic energy and potential energy
For kinetic energy :
Maximum when the displacement is zero
This is because kinetic energy can be calculated by
12mv2 and the velocity is maximum when displacement is zero so gains maximum kinetic energy when displacement is zero
For potential energy :
Maximum when displacement is maximum
This is because all the kinetic energy is transferred to potential energy as the height above the equilibrium position increases
C.1.5-1 annotated diagram of pendulum
For total energy :
Remains constant during SHM
Because total energy is addition of kinetic energy and potential energy and the transition between kinetic energy and potential energy constantly happens during SHM so the total energy remains constant
C.1.5-2 Combined graph with diagram of energy transition of pendulum SHM