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C.3 Wave Phenomena

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2024/07/05 08:37
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C.3.1 Wavefronts and rays, Amplitude and Intensity

Wave characteristics and definitions
Terminology
Definition
displacement, xx
instantaneous distance from equilibrium with direction (change in position); [m]
amplitude, AA
maximum displacement from the mean position (fixed average point); [m]
frequency, ff
number of oscillations done per unit time; [Hz=s1][Hz = s^{-1}] (cycles per second)
period,T T
time taken for one complete oscillation; [s] T=1fT=\frac1f
wave speed, cc
speed in ms2ms^{-2} at which the wavefronts pass a stationary observer
intensity, II
power per unit area that is received by the observer; [Wm2Wm^{-2}] • intensity is proportional to the square of its amplitude IA2I ∝ A^{2}
coherent
when two or more waves are coherent, their frequencies are identical and they have constant phase difference
Waves can be described in terms of the motion of a wavefront and/or in terms of rays.
Wavefronts: surface joining neighboring points where oscillations are in phase with each other
Can be curves or straight lines
Always perpendicular to the direction of wave propagation
C.3.1-1 Diagram of progressing wave with notations
(distance between successive wavefronts) = (λ\lambda of the wave)
C.3.1-2 Graph of transverse wave with key-terms notated
Rays: path taken by the wave energy propagation
Indicate the direction of wave propagation
Are perpendicular to wavefronts
C.3.1-3 Diagram of wave with source at the centre with rays and wavefront
Amplitude and Intensity
Amplitude and intensity depends on the energy of the wave.
The intensity
I is the amount of energy that a wave brings to a unit area every second
Intensity=Power (W)Area (m2)\textit{Intensity} = \frac{\textit{Power} \ (W)}{\textit{Area} \ (m^2)} Unit : [Wm2Wm^{-2}]
C.3.1-4 dimensional diagram that explaining the intensity in area
Power can be defined as amount of energy transmitted per unit time
P=EtP=\frac Et
So, intensity is proportional to power
IPI∝ P
And in simple harmonic motion, total energy of wave was proportional to amplitude of wave
Etotal=12mω2x02Etotalx02(x0=Amplitude)E_{\text{total}} = \frac{1}{2} m \omega^2 x_0^2 \quad \rightarrow \quad E_{\text{total}} \propto x_0^2 \quad (x_0 = \text{Amplitude})
IEtotalx02Ix02I \propto E_{\text{total}} \propto x_0^2 \quad \rightarrow \quad I \propto x_0^2
As a conclusion, intensity is proportional to the square of its amplitude
IA2(since EA2)I \propto A^2 \quad (\text{since} \ E \propto A^2)
C.3.1-5 Wave of transverse wave with amplitude notated
Inverse Square Law of Radiation
When emitted by a point source S, waves will spread out in all directions, meaning the total energy and power received by the observer will decrease as the energy spreads out over a larger area.
Surface area of a sphere of radius r:
A=4πr2A=4\pi r^2
The power received per unit area at a distance r away from the point source:
I=P4πr2I = \frac{P}{4\pi r^2}
Inverse square law: for a given area, the intensity of the received radiation is inversely proportional to the square of the distance from the point source (applied for all waves)
I1r2I \propto \frac{1}{r^2}
C.3.1-6 diagram showing the inverse square law in 3D

C.3.2 Superposition

Superposition
Waves interfere when two or more coherent waves meet, and the total displacement is the vector sum of their individual displacements.
The principle of superposition: the overall displacement at a point where one or more waves interfere is the ‘vector sum’ of the displacement of individual waves
C.3.2-1 graphs showing result of constructive and destructive interference
Types of Interference (Constructive / Destructive)
Constructive Interference
path difference : n (n=0,1,2,3,4,5......)
phase difference : 0°in phase
C.3.2-2 Notated Diagram of constructive interference
Destructive Interference
path difference :
(n+12) (n=0,1,2,3,4,5......)
phase difference : 180° () → out of phase
C.3.2-3 Notated Diagram of destructive interference

C.3.3 Polarization

Polarization of waves
Polarization only occurs to transverse waves (e.g. light).
Polarization of EM waves refers to the orientation of the oscillation in the electric field.
C.3.3-1 Diagram and graph of polarization with notations
Unpolarized : vibration varies randomly
plane-polarized : fixed plane of vibration
Partial polarization: when there is restriction to direction of vibration but not 100%
Polarization by reflection - Brewster’s law
The reflected ray is always partially plane-polarized for light incident on the boundary of two media.
Reflected ray is totally plane-polarized if the reflected ray and the refracted ray are at 90°.
Polarizing angle: angle of incidence for such condition
C.3.3-2 Digram of reflected and refracted wave with explanations
θi+θr=90\theta_i + \theta_r = 90^\circ
Brewster’s law relates the refractive index of media, to the incident angle i:
n2n1=sinθisinθr=sinθicosθi=tanθi\frac{n_2}{n_1} = \frac{\sin\theta_i}{\sin\theta_r} = \frac{\sin\theta_i}{\cos\theta_i} = \tan\theta_i
Thus, when the angle of incidence is equal to Brewster’s angle, the reflected ray is totally polarized and is perpendicular to the refracted ray.
Polarizers and Analyzers
Polarizer : any device that produces plane-polarized light from an unpolarized light
Reduces the intensity of unpolarized light by 50%
Analyzer : a polarizer used to detect polarized light
When polarized light passes through a polarizer, the intensity is reduced by a factor dependent on the orientation of the polarizer
Malus’ law
The preferred direction of the plane-polarized light incident on an analyser will allow a component of light to be transmitted:
C.3.3-3 Diagrams of plane-polarized light with certain angle with notations
Intensity of light is proportional to A2A^2
Transmitted intensity IE2,I0E02,IE02cos2θ I ∝ E^2, I_0 ∝ E_0^2, I ∝ E_0^2cos^2 \theta
I=I0cos2I=I_0cos^2
I=transmitted intensity [Wm2Wm^{-2}], I0=initialincidentintensity[Wm2]I_0=initial\,incident\,intensity [Wm^{-2}]
θ=anglebetweenplaneofvibrationandtheanalyserspreferreddirection\theta=angle between plane of vibration and the analyser's preferred direction
C.3.3-4 Diagram of polarization effect experiment
θ=90°nolighttransmittedbythe analyzer\theta=90° → no\, light transmitted\, by\, the\, analyzer

C.3.4 Reflection and refraction, Snell's law, critical angle and total internal reflection

Reflection
Angle of incidence = Angle of reflection
Inverted when reflected from a fixed end, Not inverted when reflected from a free end
C.3.4-1 Notated diagram of reflected wave
Refraction: the change in direction of a wave when it transmits from one medium to another
Angle of incidence and refraction can be determined using Snell’s law
Snell's law
n1n2=sinθ2sinθ1n1,n2=refractive indices of media\frac{n_1}{n_2} = \frac{\sin\theta_2}{\sin\theta_1} \\ n_1, \, n_2 = \textit{refractive indices of media}
Waves move slower in denser media (higher refractive index)
fast to slow: transmits towards the normal line, slow to fast: away from normal
C.3.4-2 Digram of refraction with notations
Refractive indices n1n_1 and n2n_2 are related by the following equation
n1n2=sinθ2sinθ1=λ2λ1=v2v1\frac{n_1}{n_2} = \frac{\sin\theta_2}{\sin\theta_1} = \frac{\lambda_2}{\lambda_1} = \frac{v_2}{v_1}
C.3.4-3 refracted wave in certain surface with notation
Total internal reflection and critical angle
Total internal reflection occurs when the angle of incidence is greater than the critical angle.
sinθc=1n1,θc=critical angle\sin\theta_c = \frac{1}{n_1}, \quad \theta_c = \textit{critical angle}
It only occurs when the light ray propagates from a optically denser medium to a less dense medium.

C.3.5 Diffraction through a single-slit and around objects

Diffraction: the bending of waves around obstacles in their path
Phenomenon where waves spread around obstacles and tend to spread out when they pass through apertures is called diffraction.
Wavelength must be of the same order of magnitude as the aperture for noticeable diffraction.
Diffraction becomes significant when wavelength becomes relatively large in comparison to the size of the aperture.
The frequency, wavelength, speed of waves remains the same after diffraction
Direction of propagation changes.
Amplitude becomes less than that of the incident wave as energy is distributed over a large area.
C.3.5-1 Single-slit diffraction pattern

C.3.6 Interference patterns, Double-slit interference, Path difference

Interference
Maximums are formed at constructive interference and minimums are formed at destructive interference.
C.3.6-1 Interference of light waves
Double-slit interference
Double-slit diffraction occurs through the same mechanism of single slit diffraction and interference.
C.3.6-2 wave from two sources
If two rays result in a bright patch, then they must arrive in phase.
The extra distance that the ray that travels a longer path exceeds is called the path difference.
Path difference=n, n=1, 2, 3, ...
Path difference=nλ,n=1,2,3,Also, Path difference=dsinθnλ=dsinθ\textit{Path difference} = n\lambda, \quad n = 1, 2, 3, \dots\\ \textit{Also, Path difference} = d \sin\theta\\ n\lambda = d \sin\theta
C.3.6-3 interference of waves from slits with notation
Xn=nλDsd=Xn+1Xn=λDss=λDds=distancebetweentwofringes,D=distancebetweensourceandscreen,d=fringe separationX_n = \frac{n\lambda D}{s}\\ d = X_{n+1} - X_n = \frac{\lambda D}{s}\\ s = \frac{\lambda D}{d}\\ s=distance\, between\, two \, fringes,D=distance\, between \, source\, and\, screen,d=fringe\,  separation
C.3.6-4 Fringe pattern from Young’s Double slit Experiment
The path difference must be:
nλ where n=0,1,2, for constructive interference(n+12)λ where n=0,1,2, for destructive interferencen is the order of the fringe, n=0 being the zeroth ordern\lambda \textit{ where } n = 0, 1, 2, \dots \textit{ for constructive interference}\\ (n + \frac{1}{2})\lambda \textit{ where } n = 0, 1, 2, \dots \textit{ for destructive interference}\\ n \textit{ is the order of the fringe, } n = 0 \textit{ being the zeroth order}

C.3.7 The Nature of Single-Slit Diffraction

The Nature of Single-Slit Diffraction
When plane waves are incident normally on a single slit, a diffraction pattern is produced
This is represented as a series of light and dark fringes which show the areas of maximum and minimum intensity
If a laser emitting blue light is directed at a single slit, where the slit width is larger than the wavelength of the light, it will spread out as follows :
C.3.7-1 Combined graph with diagram of Single slit diffraction pattern
The features of the single-slit diffraction pattern using monochromatic light :
A central maximum with a high intensity
Equally spaced subsidiary maxima, successively smaller in intensity and half the width of the central maximum
White Light Single Slit Diffraction
C.3.7-2 Diagram of diffraction pattern of white light
If the laser were to be replaced by a non-laser source emitting white light :
The central maximum would be white
All maxima would be composed of a spectrum
The shortest wavelength (violet / blue) would appear nearest to the central maximum
The longest wavelength (red) would appear furthest from the central maximum
The fringe spacing would be smaller and the maxima would be wider
Equation in Single Slit Diffraction
The relationship between angle of diffraction and wavelength of the light can be represented by equation :
θ=λ2\theta = \frac{\lambda}{2}
If refers that the angle if diffraction is directly proportional to the wavelength of the light
C.3.7-3 Annotated diagram of Single slit diffraction
From the equation the angle represents the angular separation from cetre to first minimum
The equation can be used for second and third minimum appeared at the diffraction pattern

C.3.8 Effect on Intensity of Maxima and Minima

Intesity of Maxima and Minima
Using different sources of monochromatic light demonstrates
Increasing the wavelength increases the width of the fringes
The angle of diffraction of the first minima can be found using the equation :
θ=λ2\theta = \frac{\lambda}{2}
This equation explains why red light produces wider maxima
It is because the longer the wavelength, λ, the larger the angle of diffraction, θ
It also explains the coloured fringes seen when white light is diffracted
It is because red light (longer λ) will diffract more than blue light which has shorter wavelength
This creates fringes which are blue nearer the centre and red further out
It also explains why wider slits cause the maxima to be narrower
It is because the wider the slit the smaller the angle of diffraction
C.3.8-1 Diffraction pattern

C.3.9 Young’s Double-Slit Experiment

Young’s Double-Slit Experiment
C.3.9-1 annotated diagram of Young’s Double-Slit Experiment
When a monochromatic light source is placed behind a single slit, the light is diffracted producing two light sources at the double slits A and B
Since both light sources originate from the same primary source, they are coherent and will therefore create an observable interference pattern
Both diffracted light from the double slits create an interference pattern made up of bright and dark fringes
By using the trigonometric equations we can evaluate the equation involving wavelength of the light, distance between double slit to screen, fringe width and distance between slits :
C.3.9-2 annotated equation and relative diagram
The Effect of Single slit Diffraction on Young’s Double-Slit Experiment
Young’s Double Slit experiment had assumption that the slits are infinitely small that only wavefronts of source pass through the slit
C.3.9-3 Diagram of original fringe pattern
This assumption is including that the single wavelet of wavefronts are perfectly spherical and the energy distribution is even over the spherical wavefront
It enables each slit to be treated as a point source and the interference pattern considered has regular peak maxima
The slits have finite width
This allows that the wavefronts would not perfectly spherical after passing the slits and due to the single slit diffraction effect the intensity distribution is not even
The intensity distribution follow the single slit diffraction pattern
C.3.9-4 annotated diagram of realistic Young’s Double Slit Experiment
This concludes that Young’s double slit experiment entails both features of interference pattern and diffraction pattern

C.3.10 Diffraction Grating

Diffraction Grating Patterns
A diffraction grating is a plate consisting of a very large number of parallel, identical, close-spaced slits
C.3.10-1 Diagram of Diffraction Grating Experiment
On the diffraction pattern as the number of slits increases (Maxima and Minima) :
Between the maxima, secondary maxima appear
The central maxima and subsequent bright fringes become narrower
C.3.10-2 Diagram of Diffraction Grating results
On a diffraction pattern, as the number of slits increases (Intesity) :
The intensity of the central and other larger maxima increases
Since the overall amount of light being let through each slit is increased, the pattern increases in intensity
Equation for Diffraction Grating
From the experiment of Diffraction grating
Equation of Diffraction grating can be evaluated including the angular separation between the order of maxima, distance between neighboring slits, wavelength of the source and order of maxima :
C.3.10-3 annotated equation of diffraction grating

C.3.11 Thin Film Effect

Thin Film Effect
The effect is caused by the reflection of waves from the top and bottom surface of the thin film
For thin film effect to happen :
The film has to have higher refractive index than the medium surrounding it
It has to transmit the light
C.3.11-1 Thin Film diagram
When light is incident on the surface A light wave reflects with phase change (wave 1)
Because light wave is experiencing reflection at the boundary between less dense to more dense medium
Involving the diagram above, the light wave on surface A experiences reflection and undergoes a phase change of half a wavelength in terms of path difference and /180° difference in terms of phase difference
When refracted light wave is incident on the surface B light wave reflects with no phase chage (wave 2)
Because during the wave is passing through from less dense to more dense medium both reflection and refraction happens
So the part of the light wave passes through the film and incident on the boundary between film and air (surface B)
Then the light wave ib surface B is at the boundary of more dense to less dense medium so the reflection undergoes without a phase change
Then after both waves are out of the film (wave 1 and wave 2) they interfere and forms constructive or destructive interference with certain conditions
The condition for constructive and destructive interference to happen can be organized by the equation
For constructive interference, normally constructive interference occurs when two waves are in phase
But in this case one of the light wave is already had phase change so the path difference need to be half wavelength
So the equation can be established :
2dn=(m+12)λ(d=thickness of the film,n=refractive index of medium,m=integer)2dn = \left(m + \frac{1}{2} \right) \lambda\\ (d = \textit{thickness of the film}, \quad n = \textit{refractive index of medium}, \quad m = \textit{integer})
The condition for destructive interference to happen can be organized by the equation
For destrictive interference, it occurs when two waves are out of phase
Because one wave is already had phase change of 180°, so get out of phase again
The path difference should be multiple of wavelength
So the equation can be established :
2dn=mλ(d=thickness of the film,n=refractive index of medium,m=integer)2dn = m\lambda\\ (d = \textit{thickness of the film}, \quad n = \textit{refractive index of medium}, \quad m = \textit{integer})
(d=thicknesso of the film, n=refractive index of medium, m=integer)
In case when there is another medium at the bottom of the film with higher refractive index then film
The refracted wave will experience phase change again
So the condition for constructive and destructive index will be exactly opposite